Blackjack Strategy Guide

Your Guide To All Things Blackjack

A question for the game that geniuses! HELP with probability …? Ke do?

THE PROBLEM: In a large casino, the bank earns on its blackjack tables with a probability of 50.7%. All Paris Blackjack are 1 to 1: If you win, you win the amount you bet, if you lose, you lose the game. Q: If you bet $ 1 in each hand, what is the value you expected from a single set? What is the house advantage? The answer is – $ 0,014 advantage of home listings is $ 0.14 PLEASE explain, I have no idea how to get there!

The expected value is the net amount of pocket at the end of the game. E = (money you earn) * (Probability rack) – (money lost) * (Probability of losing) money you earn depends on the probability of winning. If P is the probability that you win and you win the amount you bet (B) if and when you win, and lose your bet if you lose, you gain an average of BP – B (1) per set P (probability of winning the money game time you earn less likely they lost both the amount of money lost. Finally, E = BP-B (1-p) = B (2P-1) the probability that the house wins 50.7%, or 0507. The probability that winning is 1-0.507 = 0,493 E = 1 $ * (2 * 0.493-1) = – $ 0,014 is lost an average of 1.4 cents a game where, if you bet $ 1 on each game. The house advantage is usually expressed as a percentage of the house, is expected to win each game on average. If you lose an average 1.4% of their games (1.4 cents for every dollar you BET), the house advantage is usually defined as 1.4%. provided that the response (0.14 $) Money is the average home victories to 10 games.

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